4x^2-4x+5=0

Solution for 4x^2-4x+5=0 equation:

Simplifying
4x2 + -4x + 5 = 0

Reorder the terms:
5 + -4x + 4x2 = 0

Solving
5 + -4x + 4x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
1.25 + -1x + x2 = 0

Move the constant term to the right:

Add '-1.25' to each side of the equation.
1.25 + -1x + -1.25 + x2 = 0 + -1.25

Reorder the terms:
1.25 + -1.25 + -1x + x2 = 0 + -1.25

Combine like terms: 1.25 + -1.25 = 0.00
0.00 + -1x + x2 = 0 + -1.25
-1x + x2 = 0 + -1.25

Combine like terms: 0 + -1.25 = -1.25
-1x + x2 = -1.25

The x term is -1x.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1x + 0.25 + x2 = -1.25 + 0.25

Reorder the terms:
0.25 + -1x + x2 = -1.25 + 0.25

Combine like terms: -1.25 + 0.25 = -1
0.25 + -1x + x2 = -1

Factor a perfect square on the left side:
(x + -0.5)(x + -0.5) = -1

Can't calculate square root of the right side.

The solution to this equation could not be determined.